源碼
\begin{array}{lr}
& x+1 \\
x+1 \!\!\!\!\!\! & \overline{)x^2 + 2x + 1} \\
& \underline{x^2+\ \ x\ \ \ \ \ \ \ } \\
& x + 1 \\
& \underline{x+1} \\
& 0
\end{array}
效果
x+1x+1???????????)x2+2x+1￣x2+x￣x+1x+1￣0\begin{array}{lr} & x+1 \\ x+1 \!\!\!\!\!\! & \overline{)x^2 + 2x + 1} \\ & \underline{x^2+\ \ x\ \ \ \ \ \ \ } \\ & x + 1 \\ & \underline{x+1} \\ & 0 \end{array} x+1?x+1)x2+2x+1?x2+??x????????x+1x+1?0?
