目錄

一、題目

二、代碼

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一、題目

二、代碼

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/*** Definition for a binary tree node.* struct TreeNode {*     int val;*     TreeNode *left;*     TreeNode *right;*     TreeNode() : val(0), left(nullptr), right(nullptr) {}*     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}*     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}* };*/
class Solution {
public:int PreOrder(TreeNode*root,int sum){if(root == nullptr){return 0;}sum=sum<<1 |root->val;if(root->left==nullptr && root->right==nullptr){return sum;}return PreOrder(root->left,sum)+PreOrder(root->right,sum);}int sumRootToLeaf(TreeNode* root) {int sum=0;return PreOrder(root,sum);}
};