Android判斷界面

???? 仿造微信，第一次進入去引導界面，否則進啟動界面。

package edu.hpu.init;

import edu.hpu.logic.R;

import android.app.Activity;

import android.content.Intent;

import android.content.SharedPreferences;

import android.os.Bundle;

import android.os.Handler;

import android.os.Message;

public class TellActivity extends Activity {

	boolean isFirstIn = false;

	private static final int GO_HOME = 1000;

	private static final int GO_GUIDE = 1001;

	// 延遲3秒

	private static final long delayTime = 3000;

	private static final String spName = "first_pref";

	private Handler mHandler = new Handler() {

		@Override

		public void handleMessage(Message msg) {

			switch (msg.what) {

			case GO_HOME:

				goHome();

				break;

			case GO_GUIDE:

				goGuide();

				break;

			}

			super.handleMessage(msg);

		}

	};

	@Override

	protected void onCreate(Bundle savedInstanceState) {

		super.onCreate(savedInstanceState);

		setContentView(R.layout.splash);

		init();

	}

	private void init() {

		// 讀取SharedPreferences中需要的數據

		// 使用SharedPreferences來記錄程序的使用次數

		//接口，MODE_PRIVATE指定該SharedPreferences數據只能被本應用程序讀、寫

		SharedPreferences preferences = getSharedPreferences(

				spName, MODE_PRIVATE);

		SharedPreferences.Editor editor; 

		editor = preferences.edit();

		// 取得相應的值，如果沒有該值，說明還未寫入，用true作為默認值

		isFirstIn = preferences.getBoolean("isFirstIn", true);

		// 判斷程序第幾次運行，如果是第一次運行則跳轉到引導界面，否則跳轉到主界面

		if (!isFirstIn) {

			mHandler.sendEmptyMessageDelayed(GO_HOME, delayTime);

		} else {

			// 使用Handler的postDelayed方法，3秒后執行GuideActivity

			mHandler.sendEmptyMessageDelayed(GO_GUIDE, delayTime);

			editor.putBoolean("isFirstIn", false);

			editor.commit();

		}

	}

	private void goHome() {

		Intent intent = new Intent(this, StartActivity.class);

		startActivity(intent);

		this.finish();

	}

	private void goGuide() {

		Intent intent = new Intent(this, GuideActivity.class);

		startActivity(intent);

		this.finish();

	}

}