Java for LeetCode 061 Rotate List

Given a list, rotate the list to the right by k places, where k is non-negative.

For example:
Given 1->2->3->4->5->NULL and k = 2,
return 4->5->1->2->3->NULL.

解題思路：

只需找到對應的位置，然后指向head，接著把之前節點指向null即可，注意k可以取大于length的值，所以k%=length，JAVA實現如下：

    public ListNode rotateRight(ListNode head, int k) {if(head==null||head.next==null)return head;ListNode temp=head;int length=1;while(temp.next!=null){temp=temp.next;length++;}if(k==length)return head;temp.next=head;temp=head;for(int i=1;i<length-k;i++)temp=temp.next;head=temp.next;temp.next=null;return head;}

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