1、輸入一個整數列表，將列表中的元素按照逆序輸出。
list1=[5,4,5,6]
list1.reverse()
print(list1)
[6, 5, 4, 5]
2、輸入一個字符串列表，輸出其中長度大于等于5的字符串，并且將它們轉換為大寫形式。
list1=['hello','lol','ak47','aliang']
for i in list1:if len(i) >=5:print(i.upper())
HELLO
ALIANG
3、輸入一個整數列表，輸出該列表中所有奇數的平方和。
list1=[1,2,3,4,5,6,7,8,9]
sum = 0
for num in list1:if num % 2 == 1:sum += num ** 2
print(sum)
165
4、輸入一個列表，輸出該列表中所有正整數的和。
list1=[-5,-1,0,1,2,3,1.7,'i']
sum = 0
for num in list1:if isinstance(num, (int)) and num > 0 :sum+= num
print(sum)
6
5、輸入一個列表，輸出該列表中所有偶數的平均值。
list1=[-5,-1,0,1,2,3,1.7,'i']
sum = 0
i = 0
for num in list1:if isinstance(num, (int)) and num % 2 == 0 :sum+= numi+=1
print(sum/i)
1.0
6、已知一個數字列表，求所有元素和。
lst = [51, 54, 85, 45, 80, 45, 12, 96, 789, 45, 69]
lst = [51, 54, 85, 45, 80, 45, 12, 96, 789, 45, 69]
sum = 0
for numb in lst:sum += numb
print(sum)
1371
7、已知一個數字列表，輸出所有奇數下標元素。
lst = [59, 54, 89, 45, 78, 45, 12, 96, 789, 45, 69]
lst = [59, 54, 89, 45, 78, 45, 12, 96, 789, 45, 69]
for j in range(len(lst)):if j % 2 == 1:print(lst[j])
54
45
45
96
45
8、已知一個數字列表，輸出所有元素中，值為奇數的元素。
lst = [59, 54, 89, 45, 78, 45, 12, 96, 789, 45, 69]
lst = [59, 54, 89, 45, 78, 45, 12, 96, 789, 45, 69]
for i in lst:if i % 2 == 1:print(i)
59
89
45
45
789
45
69
9、已知一個數字列表，將所有元素乘二。
nums = [1, 2, 3, 4]
nums = [1, 2, 3, 4]
for j in range(len(nums)):nums[j] = nums[j] * 2
print(nums)
[2, 4, 6, 8]
10、有一個長度是10的列表，數組內有10個人名，要求去掉重復的
例如:names = [‘張三’, ‘李四’, ‘大黃’, ‘張三’] -> names = [‘張三’, ‘李四’, ‘大黃’]
names = ['張三', '李四', '大黃', '張三','小黑','小白','小明','小紅']
names = ['張三', '李四', '大黃', '張三', '小黑', '小白', '小明', '小紅']
names_unique = []
for name in names:if name not in names_unique:names_unique.append(name)print(names_unique)
['張三', '李四', '大黃', '小黑', '小白', '小明', '小紅']
11、有一個數字列表，獲取這個列表中的最大值.(注意: 不能使用max函數)
nums = [19, 89, 90, 600, 1]
nums = [19, 89, 90, 600, 1]
max_nums = 0
for i in nums:if i > max_nums:max_nums = i
print(max_nums)
600
12、用一個列表來保存一個節目的所有分數，求平均分數(去掉一個最高分，去掉一個最低分，求最后得分)
scores = [9.8, 9.5, 9.9, 9.3, 8.9, 9.5, 9.6, 9.3, 9.4, 9.6]
scores = [9.8, 9.5, 9.9, 9.3, 8.9, 9.5, 9.6, 9.3, 9.4, 9.6]
min_score = 10
min_num = 0
max_score = 0
max_num = 0
for i in range(len(scores)):if scores[i] > max_score:max_score = scores[i]max_num = iif scores[i] < min_score:min_score = scores[i]min_num = i
del scores[min_num]
del scores[max_num]
sum_score = 0
for score in scores:sum_score += score
avg_score = sum_score / len(scores)
print(avg_score)
9.5
scores = [9.8, 9.5, 9.9, 9.3, 8.9, 9.5, 9.6, 9.3, 9.4, 9.6]# 對分數列表進行排序
scores.sort()# 去掉一個最高分和一個最低分
scores = scores[1:-1]sum_score = 0
for score in scores:sum_score += score
avg_score = sum_score / len(scores)
print(avg_score)
9.5
13、有兩個列表A和B，使用列表C來獲取兩個列表中公共的元素
例如: A = [1, ‘a’, 4, 90] B = [‘a’, 8, ‘j’, 1] --> C = [1, ‘a’]
A = [1, 'a', 4, 90]
B = ['a', 8, 'j', 1]
C = []
for i in A:if i in B:C.append(i)
print(C)
[1, 'a']
14、獲取列表中出現次數最多的元素
nums = [1, 2, 3,1,4,2,1,3,7,3,3]
nums = [1, 2, 3,1,4,2,1,3,7,3,3]
res = 0
res_i = 0
for i in nums:if nums.count(i) > res:res = nums.count(i)res_i = i
print(res_i)
3
15、將scores中所有的及格的分數提取出來
scores = [89, 67, 56, 90, 98, 30, 78, 51, 99]
scores = [89, 67, 56, 90, 98, 30, 78, 51, 99]
scores_pass = []
for score in scores:if score >= 60:scores_pass.append(score)
print(scores_pass)
[89, 67, 90, 98, 78, 99]
16、輸入一個整數列表，輸出其中最大的兩個元素的乘積。
lst=[2,6,7,10,3,5,4,9,8]
lst.sort(reverse=True)
print(lst[0]*lst[1])90
17、已知一個數字列表，求所有元素的平均數
lst = [59, 54, 89, 45, 78, 45, 12, 96, 789, 45, 69]
lst = [59, 54, 89, 45, 78, 45, 12, 96, 789, 45, 69]
sum_score = 0
for score in lst:sum_score += score
avg_score = sum_score / len(lst)
print(avg_score)
125.54545454545455
18、輸入一個字符串列表，輸出其中最長的字符串。
lst = ['apple', 'banana', 'pear', 'orange', 'kiwi', 'mango']
lst = ['apple', 'banana', 'pear', 'orange', 'kiwi', 'mango']
res = []
num = 0
for k in lst:if len(k) > num:num = len(k)res = [k]elif len(k) == num:res.append(k)
print(res)
['banana', 'orange']
19、輸入一個字符串列表，輸出其中第一個字母是元音字母的單詞（不區分大小寫）。
lst = ['apple', 'Banana', 'pear', 'Orange', 'kiwi', 'mango']
lst = ['apple', 'Banana', 'pear', 'Orange', 'kiwi', 'mango']
vowels = ['a','e','i','o','u','A','E','I','O','U']
for fruit in lst:for char in vowels:if fruit.startswith(char):print(fruit)
apple
Orange
20、已有兩個列表，輸出它們的笛卡爾積。
lst1 = [1, 2, 3]
lst2 = ['a', 'b','c']
lst1 = [1, 2, 3]
lst2 = ['a', 'b','c']
for i in lst1:for j in lst2:print(i, j)
1 a
1 b
1 c
2 a
2 b
2 c
3 a
3 b
3 c
)
