上兩節課都是對一個數組進行處理。這節我們來個有意思的。同樣是旋轉。但我們旋轉的對象是張(256*256)的圖片。圖片旋轉45度,旋轉后大小還是256*256,超出部份進行剪除。
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圖片旋轉處理有個特別的地方。buf_A是存儲源圖數據(R,G,B顏色分量),buf_B是存儲旋轉后數據。我們不能簡單將buf_A中的數據直接計算旋轉后位置。而是遍歷buf_B每個數據,計算那些數據旋轉后存在這個位置的數據他在buf_A的坐標是多少。為什么呢?不是因為不能直接旋轉。而是因為坐標是整數型。進行旋轉計算后會得出浮點數,有小數。計算精度不同。如果還用直接旋轉計算方法。成出的位圖將會出現斑點。大家可試下。
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我們來看源碼
rotate.cl源碼
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 | __kernel void rotation(__global int * A, ???????????????????? __global int * B, ???????????????????? int width, ???????????????????? int height, ???????????????????? float sinangle, ???????????????????? float cosangle) { ???? //獲取索引號,這里是二維的,所以可以取兩個 ???? //否則另一個永遠是0 ???? int col = get_global_id(0); ???? int row = get_global_id(1); ???? //計算圖形中心點 ???? float cx = (( float )width)/2; ???? float cy = (( float )height)/2; ???? int nx = ( int )(cx + cosangle * (( float )col-cx) + sinangle * (( float )row-cy)); ???? int ny = ( int )(cy + (-1*sinangle) * (( float )col-cx) + cosangle * (( float )row-cy)); ???? //邊界檢測 ???? if (nx>=0 && nx<width && ny>=0 && ny<height) ???? { ???????? B[col*3+0+row*width*3] = A[nx*3+0+ny*width*3]; ???????? B[col*3+1+row*width*3] = A[nx*3+1+ny*width*3]; ???????? B[col*3+2+row*width*3] = A[nx*3+2+ny*width*3]; ???? } } |
main.cpp源碼
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 202 203 204 205 206 207 208 209 210 211 212 213 214 215 216 217 218 219 220 221 222 223 224 225 226 227 228 229 230 231 232 233 234 235 236 237 238 239 240 241 242 243 244 245 | #include <iostream> #include <stdio.h> #include <string.h> #include <string> #include <conio.h> #include <math.h>//數學庫 #include <CL/cl.h>//包含CL的頭文件 //調用freeimage #include <freeimage.h> using namespace std; //8x8數組 const int dim_x = 256; const int dim_y = 256; //45度的弧度 const float angle = 3.1415926f/4.0f; static int buf_A[dim_x*dim_y*3]; static int buf_B[dim_x*dim_y*3]; //加載圖片 //以RGBA格式存儲圖片 static bool LoadImg( const char * fname) { ???? //初始化FreeImage ???? FreeImage_Initialise(TRUE); ???? //定義圖片格式為未知 ???? FREE_IMAGE_FORMAT fif = FIF_UNKNOWN; ???? //獲取圖片格式 ???? fif = FreeImage_GetFileType(fname,0); ???? //根據獲取格式讀取圖片數據 ???? FIBITMAP* bitmap = FreeImage_Load(fif,fname,0); ???? if (!bitmap) ???? { ???????? printf ( "load error!\n" ); ???????? return false ; ???? } ???? int x,y; ???? RGBQUAD m_rgb; ???? //獲取圖片長寬 ???? int width = ( int )FreeImage_GetWidth(bitmap); ???? int height = ( int )FreeImage_GetHeight(bitmap); ???? //獲取圖片數據 ???? //按RGBA格式保存到數組中 ???? for (y=0;y<height;y++) ???? { ???????? for (x=0;x<width;x++) ???????? { ???????????? //獲取像素值 ???????????? FreeImage_GetPixelColor(bitmap,x,y,&m_rgb); ???????????? //將RGB值存入數組 ???????????? buf_A[y*width*3+x*3+2] = m_rgb.rgbRed; ???????????? buf_A[y*width*3+x*3+1] = m_rgb.rgbGreen; ???????????? buf_A[y*width*3+x*3+0] = m_rgb.rgbBlue; ???????? } ???? } ???? FreeImage_Unload(bitmap); ???? return true ; } static bool SaveImg() { ???? //初始化FreeImage ???? FreeImage_Initialise(TRUE); ???? FIBITMAP* bitmap =FreeImage_Allocate(dim_x,dim_y,32,8,8,8); ???? int m,n; ???? for (n=0;n<dim_y;n++) ???? { ???????? BYTE *bits =FreeImage_GetScanLine(bitmap,n); ???????? for (m=0;m<dim_x;m++) ???????? { ???????????? bits[0] = buf_B[dim_x*3*n+m*3+0]; ???????????? bits[1] = buf_B[dim_x*3*n+m*3+1]; ???????????? bits[2] = buf_B[dim_x*3*n+m*3+2]; ???????????? bits[3] = 255; ???????????? bits+=4; ???????? } ???? } ???? //保存圖片為PNG格式 ???? if ( false ==FreeImage_Save(FIF_PNG, bitmap, "rotate.png" , PNG_DEFAULT)) ???? { ???????? printf ( "save image error\n" ); ???? } ???? FreeImage_Unload(bitmap); ???? return true ; } //從外部文件獲取cl內核代碼 bool GetFileData( const char * fname,string& str) { ???? FILE * fp = fopen (fname, "r" ); ???? if (fp==NULL) ???? { ???????? printf ( "no found file\n" ); ???????? return false ; ???? } ???? while ( feof (fp)==0) ???? { ???????? str += fgetc (fp); ???? } ???? return true ; } int main() { ???? if (LoadImg( "bk.png" )== false ) ???? { ???????? printf ( "error load bk.png!\n" ); ???????? return 0; ???? } ???? //先讀外部CL核心代碼,如果失敗則退出。 ???? //代碼存buf_code里面 ???? string code_file; ???? if ( false == GetFileData( "rotate.cl" ,code_file)) ???? { ???????? printf ( "Open rotate.cl error\n" ); ???????? return 0; ???? } ???? char * buf_code = new char [code_file.size()]; ???? strcpy (buf_code,code_file.c_str()); ???? buf_code[code_file.size()-1] = NULL; ???? //聲明CL所需變量。 ???? cl_device_id device; ???? cl_platform_id platform_id = NULL; ???? cl_context context; ???? cl_command_queue cmdQueue; ???? cl_mem bufferA,bufferB; ???? cl_program program; ???? cl_kernel kernel = NULL; ???? //我們使用的是二維向量 ???? //設定向量大小(維數) ???? size_t globalWorkSize[2]; ???? globalWorkSize[0] = dim_x; ???? globalWorkSize[1] = dim_y; ???? cl_int err; ???? /* ???????? 定義輸入變量和輸出變量,并設定初值 ???? */ ???? size_t datasize = sizeof ( int ) * dim_x * dim_y * 3; ???? //step 1:初始化OpenCL ???? err = clGetPlatformIDs(1,&platform_id,NULL); ???? if (err!=CL_SUCCESS) ???? { ???????? cout<< "clGetPlatformIDs error:" <<err<<endl; ???????? return 0; ???? } ???? //這次我們只用CPU來進行并行運算,當然你也可以該成GPU ???? clGetDeviceIDs(platform_id,CL_DEVICE_TYPE_CPU,1,&device,NULL); ???? //step 2:創建上下文 ???? context = clCreateContext(NULL,1,&device,NULL,NULL,NULL); ???? //step 3:創建命令隊列 ???? cmdQueue = clCreateCommandQueue(context,device,0,NULL); ???? //step 4:創建數據緩沖區 ???? bufferA = clCreateBuffer(context, ????????????????????????????? CL_MEM_READ_ONLY, ????????????????????????????? datasize,NULL,NULL); ???? bufferB = clCreateBuffer(context, ????????????????????????????? CL_MEM_WRITE_ONLY, ????????????????????????????? datasize,NULL,NULL); ???? //step 5:將數據上傳到緩沖區 ???? clEnqueueWriteBuffer(cmdQueue, ????????????????????????? bufferA,CL_FALSE, ????????????????????????? 0,datasize, ????????????????????????? buf_A,0, ????????????????????????? NULL,NULL); ???? //step 6:加載編譯代碼,創建內核調用函數 ???? program = clCreateProgramWithSource(context,1, ???????????????????????????????????????? ( const char **)&buf_code, ???????????????????????????????????????? NULL,NULL); ???? clBuildProgram(program,1,&device,NULL,NULL,NULL); ???? kernel = clCreateKernel(program, "rotation" ,NULL); ???? //step 7:設置參數,執行內核 ???? float sinangle = sinf(angle); ???? float cosangle = cosf(angle); ???? clSetKernelArg(kernel,0, sizeof (cl_mem),&bufferA); ???? clSetKernelArg(kernel,1, sizeof (cl_mem),&bufferB); ???? clSetKernelArg(kernel,2, sizeof (cl_int),&dim_x); ???? clSetKernelArg(kernel,3, sizeof (cl_int),&dim_y); ???? clSetKernelArg(kernel,4, sizeof (cl_float),&sinangle); ???? clSetKernelArg(kernel,5, sizeof (cl_float),&cosangle); ???? //注意這里第三個參數已經改成2,表示二維數據。 ???? clEnqueueNDRangeKernel(cmdQueue,kernel, ??????????????????????????? 2,NULL, ??????????????????????????? globalWorkSize, ??????????????????????????? NULL,0,NULL,NULL); ???? //step 8:取回計算結果 ???? clEnqueueReadBuffer(cmdQueue,bufferB,CL_TRUE,0, ???????????????????????? datasize,buf_B,0,NULL,NULL); ???? SaveImg(); ???? //釋放所有調用和內存 ???? clReleaseKernel(kernel); ???? clReleaseProgram(program); ???? clReleaseCommandQueue(cmdQueue); ???? clReleaseMemObject(bufferA); ???? clReleaseMemObject(bufferB); ???? clReleaseContext(context); ???? delete buf_code; ???? return 0; } |
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源圖
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旋轉后圖