ajax加php實現三級聯動

js代碼

<script type="text/javascript">
?? ?function get_next(t,pid){? //當前元素的id，當前option的value，一般都是id吧？反正我的是
?? ??? ?$.ajax({
?? ??? ??? ?type: "POST",
?? ??? ??? ?url:? "/index.php?type=company&m=action&a=getNext",
?? ??? ??? ?data: "pid="+pid,
?? ??? ??? ?dataType: 'json',
?? ??? ??? ?success: function(msg){
?? ??? ??? ??? ?$("#"+t).next('select').html(msg.str);//拼接html
?? ??? ??? ?}
?? ??? ?});
?? ?}
</script>

php代碼

public function getNext()
?? ??? ?{
?? ??? ??
?? ??? ??? ?$next = $sql ?? //查找數據庫pid=post過來的id的sql
?? ??? ??? ?$str = "<option value=''>請選擇</option>";
?? ??? ??? ?foreach ($next as $val) {
?? ??? ??? ??? ?$str .= "<option value='".$val['id']."'>".$val["name"]."</option>";
?? ??? ??? ?}
?? ??? ??? ?$msg["str"] = $str;
?? ???????? echo json_encode($msg);
?? ???????? die();
?? ??? ?}

?

可以在任何地方調用，但是還是有個小缺陷，我選擇無視。嘻嘻