?邏輯或 ||
int i, j, k;
i = 0x15;
j = 0x41;
k = i || j;
反匯編代碼如下:
MOV DWORD PTR SS:[EBP-4], 15
MOV DWORD PTR SS:[EBP-C], 41
CMP DWORD PTR SS:[EBP-4], 0
JNZ SHORT asm_OR.00401029
CMP DWORD PTR SS:[EBP-C], 0
JNZ SHORT asm_OR.00401029
MOV DWORD PTR SS:[EBP-10], 0
JMP SHORT asm_OR.00401030
MOV DWORD PTR SS:[EBP-10], 1 ? ? ? ? //這條指令的地址是 00401029
MOV EAX, DWORD PTR SS:[EBP-10] ? ?//這條指令的地址是 00401030
MOV DWORD PTR SS:[EBP-8], EAX
_______________________________________________
位或 |
int i, j, k;
i = 0x15;
j = 0x41;
k = i | j;
反匯編代碼如下:
MOV DWORD PTR SS:[EBP-4], 15
MOV DWORD PTR SS:[EBP-C], 41
MOV ECX, DWORD PTR SS:[EBP-4]
OR ECX, DWORD PTR SS:[EBP-C]? ? ? ? ? ?可見OR的兩個操作數必須有一個是寄存器, 前后都可以.
MOV DWORD PTR SS:[EBP-8], ECX?
轉載于:https://www.cnblogs.com/goalpower/p/4032592.html