C++程序設計 （第三版） 譚浩強 習題2.5

習題2.5 請寫出下列表達式的值。

(1) 3.5 * 3 + 2 * 7 - ‘a’

(2) 26 / 3 + 34 % 3 + 2.5

(3) 45 / 2 + (int)3.14159 / 2

(4) a = b = (c = a += 6) 設a的初值為3

(5) a = 3 * 5, a = b = 3 * 2

(6) (int)(a + 6.5) % 2 + (a = b = 5) 設a的初值為3

(7) x + a % 3 * (int)(x + y) % 2 / 4 設x = 2.5，a = 7，y = 4.7

(8) (float)(a + b) / 2 + (int)x % (int)y 設a = 2，b = 3，x = 3.5，y = 2.5

IDE工具：VS2010

Note: 使用不同的IDE工具可能有部分差異。

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代碼塊

#include <iostream>
using namespace std;int main(){float p1 = 3.5 * 3 + 2 * 7 - 'a';float p2 = 26 / 3 + 34 % 3 + 2.5;int p3 = 45 / 2 + (int)3.14159 / 2;int a, b, c;a = 3;int p4 = a = b = (c = a += 6);int p5;p5 = a = 3 * 5, p5 = a = b = 3 * 2;a = 3;int p6 = (int)(a + 6.5) % 2 + (a = b = 5);float x, y;x = 2.5;y = 4.7;a = 7;float p7 = x + a % 3 * (int)(x + y) % 2 / 4;a = 2;b = 3;x = 3.5;y = 2.5;float p8 = (float)(a + b) / 2 + (int)x % (int)y;cout<<"p1 = "<<p1<<endl;cout<<"p2 = "<<p2<<endl;cout<<"p3 = "<<p3<<endl;cout<<"p4 = "<<p4<<endl;cout<<"p5 = "<<p5<<endl;cout<<"p6 = "<<p6<<endl;cout<<"p7 = "<<p7<<endl;cout<<"p8 = "<<p8<<endl;system("pause");return 0;
}

結果顯示如下：