Java語言的ACM輸入輸出模版

1.多行輸入,每次輸入兩個整數

import java.lang.*;
import java.util.*;
public class Main{public static void main(String[] args){Scanner in = new Scanner(System.in);while(in.hasNextInt()){int a = in.nextInt();int b = in.nextInt();System.out.println(a+b);}}
}

2.多組數據,每組第一行為n, 之后輸入n行兩個整數

import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNext()) {int n = scanner.nextInt();while (n-- > 0) {int a = scanner.nextInt();int b = scanner.nextInt();System.out.println(a + b);}}}
}

3.若干行輸入,每行輸入兩個整數,遇到特定條件終止

import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNext()) {int a = scanner.nextInt();int b = scanner.nextInt();if (a == 0 && b == 0) {break;}System.out.println(a + b);}}
}

4.若干行輸入,遇到0終止,每行第?個數為N,表示本行后面有N個數

import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNext()) {int n = scanner.nextInt();if (n == 0) {break;}int sum = 0;for (int i = 0; i < n; i++) {sum += scanner.nextInt();}System.out.println(sum);}}
}

5.若干行輸入,每行包括兩個整數a和b,由空格分隔,每行輸出 后接?個空行。

import java.util.Scanner;
public class Main{public static void main(String[] args){Scanner sc = new Scanner(System.in);while(sc.hasNextLine()){int a = sc.nextInt();int b = sc.nextInt();System.out.println(a + b);System.out.println();}}
}

6.多組n行數據,每行先輸入一個整數N,然后在同一行內輸入M個整數,每組輸出之間輸出一個空行。

import java.util.Scanner;
public class Main{public static void main(String[] args){Scanner sc = new Scanner(System.in);while(sc.hasNextLine()){int N = sc.nextInt();// 每組有n?數據while(N-- > 0){int M = sc.nextInt();int sum = 0;// 每?有m個數據while(M-- > 0){sum += sc.nextInt();}System.out.println(sum);if(N > 0) System.out.println();}}}
}

7.多組測試樣例,每組輸?數據為字符串,字符用空格分隔,輸出 為小數點后兩位

import java.util.*;
public class Main {public static void main(String[] args) {Scanner in = new Scanner(System.in);while (in.hasNextLine()) {String line = in.nextLine(); // 接收?整?字符串作為輸?String[] items = line.split(" "); // 字符串分割成數組for (String item : items) { // 遍歷數組}}}
}

8.多組測試用例,第一行為正整數n, 第二行為n個正整數,n=0 時,結束輸入,每組輸出結果的下面都輸出?個空行

import java.util.ArrayList;
import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNext()) {Integer size = scanner.nextInt();if (size == 0) {break;}// 創建listArrayList<Integer> list = new ArrayList<>();// 添加?組數據到list中for (int i = 0; i < size; i++) {int num = scanner.nextInt();list.add(num);}// 遍歷for (int i = 0; i < list.size(); i++) {System.out.println(list.get(i));}System.out.println(res);System.out.println();}}
}

9.?多組測試數據,每組數據只有一個整數,對于每組輸入數據, 輸出一行,每組數據下方有?個空行。

import java.util.*;
public class Main {public static void main(String[] args) {Scanner in = new Scanner(System.in);while (in.hasNextInt()) {int n = in.nextInt();while (n > 0) {int tmp = n % 10; // 獲取各位數據n /= 10;}System.out.println(res);System.out.println();}}
}

10.多組測試數據,每個測試實例包括2個整數M,K (2<=k<=M<=1000)。M=0,K=0代表輸入結束。

import java.util.*;
public class Main{public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNextInt()) {int m = sc.nextInt();int k = sc.nextInt();if (m == 0 && k == 0) break;int sum = 0;System.out.println(sum);}
}
}

11.多組測試數據,首先輸入?個整數N,接下來N行每行輸入兩個整數a和b, 讀取輸入數據到Map

import java.util.*;
public class Main{static Map<Integer, Integer> map = new HashMap();public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNextInt()) {int n = sc.nextInt();for (int i = 0; i < n; i++) {int a = sc.nextInt();int b = sc.nextInt();map.put(a, b);}}}
}

12.多組測試數據。每組輸入?個整數n,輸出特定的數字圖形

import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNext()) {int n = scanner.nextInt();for (int i = 1; i <= n; i++) {print(n - i, i);}for (int i = n - 1; i >= 1; i--) {print(n - i, i);}}}public static void print(int blank, int n) {// 前?需要補?空格for (int i = 0; i < blank; i++) {System.out.print(" ");}for (int i = 1; i <= n; i++) {System.out.print(i);}for (int i = n - 1; i > 0; i--) {System.out.print(i);}System.out.println();}
}

13.多行輸入,每行輸入為?個字符和?個整數,遇到特殊字符結束

import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNext()) {String line = sc.nextLine();if (line.equals("@"))break;String[] inputs = line.split(" ");char ch = inputs[0].charAt(0);int n = Integer.parseInt(inputs[1]);}sc.close();}
}

14.第一行是?個整數n,表示?共有n組測試數據, 之后輸入n行字符串

import java.util.*;
public class Main{public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNextInt()) {int n = sc.nextInt();sc.nextLine();
for (int i = 0; i < n; i++) {String line = sc.nextLine().trim();StringBuilder sb = new StringBuilder();System.out.println(sb.toString());}}}
}

15.第?行是?個整數n,然后是n組數據,每組數據2行,每行為?個字符串,為每組數據輸出?個字符串,每組輸出占?行

import java.util.Scanner;
public class Main{public static void main(String[] args) {Scanner in = new Scanner(System.in);int n = in.nextInt();for (int i = 0; i < n; i++) {String a = in.next();String b = in.next();StringBuilder sb = new StringBuilder(a);System.out.println(sb.toString());}}
}
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {public static void main(String[] args) throws IOException {BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));String str = null;while((str = reader.readLine())!= null){
StringTokenizer tokenizer = new StringTokenizer(str);int n = Integer.parseInt(tokenizer.nextToken());for(int i = 0; i < n; i++){String a = reader.readLine();String b = reader.readLine();StringBuilder sb = new StringBuilder();System.out.println(sb.toString());}}}
}

16.多組測試數據,第?行是?個整數n,接下來是n組字符串, 輸出字符串

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {public static void main(String[] args) throws IOException {BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));String str = null;while((str = reader.readLine())!= null){StringTokenizer tokenizer = new StringTokenizer(str);int n = Integer.parseInt(tokenizer.nextToken());for(int i = 0; i < n; i++){String s = reader.readLine();StringBuilder sb = new StringBuilder();System.out.println(sb.toString());}}}
}
// ?法?:原地交換
import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner sc = new Scanner(System.in);int n = sc.nextInt();sc.nextLine();for (int i = 0; i < n; i++) {String s1 = sc.nextLine();int len = s1.length();char[] chs = s1.toCharArray();System.out.println(new String(chs));}sc.close();}
}

17.多組測試數據,每組測試數據的第?行為整數N (1<=N<=100),當N=0時,輸?結束,第二行為N個正整數, 以空格隔開,輸出結果為字符串

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.StringTokenizer;
public class Main {public static void main(String[] args) throws IOException {BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));String str = null;while((str = reader.readLine())!= null){StringTokenizer tokenizer = new StringTokenizer(str);// 讀取nint n = Integer.parseInt(tokenizer.nextToken());if(n == 0){break;}int[] arr = new int[n];tokenizer = new StringTokenizer(reader.readLine());// 讀取n個正整數for(int i = 0; i < n; i++){arr[i] = Integer.parseInt(tokenizer.nextToken());}if(check(arr)){System.out.println("Yes");}else{System.out.println("No");}}}
}
// ?法?:使?棧模擬
import java.util.Scanner;
import java.util.Stack;
public class Main {public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (true) {int n = sc.nextInt();if (n == 0)break;Stack<Integer> stack = new Stack<>();for (int i = 0; i < n; i++)
stack.push(sc.nextInt())}if (isValidPopSequence(n, poppedSequence))System.out.println("Yes");elseSystem.out.println("No");}sc.close();}
}

18.?組輸?數據,第?行為n+1個整數,逆序插?n個整數,第二行為?個整數m, 接下來有m行字符串,并根據字符串內容輸 ?不同個數的數據

public static void main(String[] args) {Scanner sc = new Scanner(System.in);// 輸?nint n = sc.nextInt();// 輸?n個整數for (int i = 0; i < n; i++) {int num = sc.nextInt();linkedList.addFirst(num);}// 輸?mint m = sc.nextInt();// 輸?m個字符串for (int i = 0; i < m; i++) {// 獲取輸?的字符串String operation = sc.next();// 根據輸?內容,給出不同輸出結果if ("get".equals(operation)) {int a = sc.nextInt();int result = linkedList.get(a - 1);if (result != -1) {System.out.println(result);} else {System.out.println("get fail");}} else if ("delete".equals(operation)) {int a = sc.nextInt();boolean deleteResult = linkedList.delete(a - 1);if (deleteResult) {System.out.println("delete OK");} else {System.out.println("delete fail");}} else if ("insert".equals(operation)) {int a = sc.nextInt();int e = sc.nextInt();boolean insertResult = linkedList.insert(a - 1, e);if (insertResult) {System.out.println("insert OK");} else {System.out.println("insert fail");}} else if ("show".equals(operation)) {linkedList.show();}}sc.close();
}

19.多組測試數據,每行為n+1個數字, 輸出鏈表或對應的字符串

import java.util.Scanner;
public class Main{public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNextLine()) {String[] str = sc.nextLine().split(" ");if (Integer.parseInt(str[0]) == 0) {System.out.println("list is empty");}ListNode dummyhead = new ListNode(-1);ListNode cur = dummyhead;//構造鏈表for (int i = 1; i < str.length; i++) {ListNode temp = new ListNode(Integer.parseInt(str[i]));cur.next = temp;cur = cur.next;if (i == str.length - 1) cur.next = null;}//輸出原鏈表ListNode pointer = dummyhead.next;while (pointer != null) {System.out.print(pointer.val + " ");pointer = pointer.next;}System.out.println();}}
}

20.多組輸入,每組輸入包含兩個字符串,輸出字符串

public class Main{public static Map<Character, Integer> map = new HashMap();public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNextLine()) {String s = sc.nextLine();String[] ss = s.split(" ");String pre = ss[0];String in = ss[1];// 構建?叉樹TreeNode res = afterHelper(pre.toCharArray(), in.toCharArray());//打印?叉樹printTree(res);System.out.println();}}public static void printTree(TreeNode root) {if (root == null) return;printTree(root.left);printTree(root.right);System.out.print(root.val);}
}

21.?組多行數據,第?行為數字n, 表示后面有n行,后面每行?為1個字符加2個整數,輸出樹節點的后序遍歷字符串

import java.util.*;
class TreeNode {char val;TreeNode left;TreeNode right;public TreeNode(char val) {this.val = val;}
}
public class Main{static TreeNode[] nodes = new TreeNode[30];public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNextInt()) {int len = sc.nextInt();for (int i = 0; i < len; i++) {// 獲取字符和左右?節點char val = sc.next().charAt(0);int left = sc.nextInt();int right = sc.nextInt();}preorder(nodes[1]);System.out.println();inorder(nodes[1]);System.out.println();
postorder(nodes[1]);System.out.println();}}public static void preorder(TreeNode root) {if (root == null) return;System.out.print(root.val);preorder(root.left);preorder(root.right);}public static void inorder(TreeNode root) {if (root == null) return;inorder(root.left);System.out.print(root.val);inorder(root.right);}public static void postorder(TreeNode root) {if (root == null) return;postorder(root.left);postorder(root.right);System.out.print(root.val);}
}
// ?法?:使?索引,簡化構建樹的過程
import java.util.Scanner;
public class Main {static class TreeNode {char val;int left;int right;public TreeNode(char val, int left, int right) {this.val = val;this.left = left;this.right = right;}}static TreeNode[] nodes;public static void main(String[] args) {Scanner sc = new Scanner(System.in);int n = sc.nextInt();nodes = new TreeNode[n + 1];for (int i = 0; i < n; i++) {char val = sc.next().charAt(0);int left = sc.nextInt();
int right = sc.nextInt();nodes[i + 1] = new TreeNode(val, left, right);}preOrderTraversal(1);System.out.println();inOrderTraversal(1);System.out.println();postOrderTraversal(1);System.out.println();sc.close();}private static void postOrderTraversal(int root) {if (root == 0)return;postOrderTraversal(nodes[root].left);postOrderTraversal(nodes[root].right);System.out.print(nodes[root].val);}private static void inOrderTraversal(int root) {if (root == 0)return;inOrderTraversal(nodes[root].left);System.out.print(nodes[root].val);inOrderTraversal(nodes[root].right);}private static void preOrderTraversal(int root) {if (root == 0)return;System.out.print(nodes[root].val);preOrderTraversal(nodes[root].left);preOrderTraversal(nodes[root].right);}
}

22.多組測試數據,首先給出正整數N,接著輸入兩行字符串, 字符串?度為N

// ?法?:遞歸
import java.util.Scanner;
public class Main {static class TreeNode {char val;TreeNode left;TreeNode right;
TreeNode(char val) {this.val = val;this.left = null;this.right = null;}}private static int getHeight(TreeNode root) {if (root == null)return 0;int leftHeight = getHeight(root.left);int rightHeight = getHeight(root.right);return Math.max(leftHeight, rightHeight) + 1;}public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNext()) {sc.nextInt();String preOrder = sc.next();String inOrder = sc.next();TreeNode root = buildTree(preOrder, inOrder);int height = getHeight(root);System.out.println(height);}sc.close();}
}
// ?法?:遞歸(使?哈希表來優化中序遍歷中查找根節點位置的過程)
import java.util.HashMap;
import java.util.Scanner;
public class Main {static class TreeNode {char val;TreeNode left;TreeNode right;TreeNode(char val) {this.val = val;
this.left = null;this.right = null;}}public static void main(String[] args) {Scanner sc = new Scanner(System.in);while (sc.hasNext()) {int N = sc.nextInt();String preOrder = sc.next();String inOrder = sc.next();HashMap<Character, Integer> inOrderMap = new HashMap<>();for (int i = 0; i < N; i++) {inOrderMap.put(inOrder.charAt(i), i);}TreeNode root = buildTree(preOrder, 0, N - 1, 0, N - 1, inOrderMap);int height = getHeight(root);System.out.println(height);}sc.close();}private static int getHeight(TreeNode root) {if (root == null) {return 0;}int leftHeight = getHeight(root.left);int rightHeight = getHeight(root.right);return Math.max(leftHeight, rightHeight) + 1;}
}

23.多組測試數據。每組輸入占一行,為兩個字符串,由若干個 空格分隔

import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNextLine()) {String line = scanner.nextLine();
String[] s = line.split(" ");String x = s[0];String y = s[1];int m = x.length();int n = y.length();// 初始化dp數組int[][] dp = new int[m + 1][n + 1];// 輸出int max = dp[m][n];System.out.println(max);}}
}

24.多組測試數據,每組第一行為兩個正整數n和m,接下來m行,每行3個整數, 最后??兩個整數

import java.util.Arrays;
import java.util.Scanner;
public class Main {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);while (scanner.hasNext()) {// 處理輸?int n = scanner.nextInt();int m = scanner.nextInt();for (int i = 0; i < m; i++) {int a = scanner.nextInt();int b = scanner.nextInt();int l = scanner.nextInt();}int x = scanner.nextInt();int y = scanner.nextInt();// 處理輸出
int res = dfs(graph, x, y, isVisit, sum);if (res != Integer.MAX_VALUE) {System.out.println(res);} else {System.out.println("No path");}}}private static int dfs(int[][] graph, int start, int end, int[] isVisit, int sum) {if (end == start) {return sum;}return min;}
}

本文來自互聯網用戶投稿,該文觀點僅代表作者本人,不代表本站立場。本站僅提供信息存儲空間服務,不擁有所有權,不承擔相關法律責任。
如若轉載,請注明出處:http://www.pswp.cn/bicheng/17515.shtml
繁體地址,請注明出處:http://hk.pswp.cn/bicheng/17515.shtml
英文地址,請注明出處:http://en.pswp.cn/bicheng/17515.shtml

如若內容造成侵權/違法違規/事實不符,請聯系多彩編程網進行投訴反饋email:809451989@qq.com,一經查實,立即刪除!

相關文章

VS2002 ~ VS2022平臺工具集對應關系

Visual Studio 版本C++編譯器版本_MSC_VER 宏工具集版本Visual Studio 6.06.01200v60Visual Studio .NET 2002 (7.0) 7.01300v70Visual Studio .NET 2003 (7.1)7.11310v71Visual Studio 2005 (8.0)

特殊成員函數實踐

文章目錄 1.構造函數一般方式2.初始化列表方式&#xff0c;構造函數3.委托構造函數4.析構函數5.淺拷貝6.深拷貝7.移動構造 1.構造函數一般方式 2.初始化列表方式&#xff0c;構造函數 3.委托構造函數 4.析構函數 5.淺拷貝 6.深拷貝 7.移動構造 #include <iostream>…

go語言方法之方法聲明

從我們的理解來講&#xff0c;一個對象其實也就是一個簡單的賦值或者一個變量&#xff0c;在這個對象中會包含一些方法&#xff0c;而一個方法則是一個一個和特殊類型關聯的函數。一個面向對象的程序會用方法來表達其屬性和對應的操作&#xff0c;這樣使用這個對象的用戶就不需…

centos6下面用yum安裝php7.3

首先安裝remi.repo 倉庫 參考: centos yum方式安裝PHP74 centos yum方式安裝PHP74_yum 安裝php74-CSDN博客 yum安裝 yum install php73-php-pecl-zip bz2 curl event gd json openssl mysqlnd PDO yum install php-posix php73 composer.phar config -g repo.packagist co…

AI大模型在測試中的深度應用與實踐案例

文章目錄 1. 示例項目背景2. 環境準備3. 代碼實現3.1. 自動生成測試用例3.2. 自動化測試腳本3.3. 性能測試3.4. 結果分析 4. 進一步深入4.1. 集成CI/CD管道4.1.1 Jenkins示例 4.2. 詳細的負載測試和性能監控4.2.1 Locust示例 4.3. 測試結果分析與報告 5. 進一步集成和優化5.1. …

IND-ID-CPA 和 IND-ANON-ID-CPA Game

Src: https://eprint.iacr.org/2017/967.pdf

算法訓練 | 二叉樹Part5 | 513.找樹左下角的值、112.路徑總和、106.從中序與后序遍歷序列構造二叉樹

目錄 513.找樹左下角的值 遞歸法 迭代法 ? 112.路徑總和 遞歸法 迭代法 106.從中序與后序遍歷序列構造二叉樹 遞歸法 513.找樹左下角的值 題目鏈接&#xff1a;513. 找樹左下角的值 - 力扣&#xff08;LeetCode&#xff09; 文章講解&#xff1a;programmercarl.com…

超聲波清洗機哪些品牌好用點?四大極其出色的機型一目了然

各位眼鏡俠們&#xff0c;在佩戴眼鏡的是&#xff0c;有沒有覺得眼鏡總是有些難以言喻的“味道”或者是污漬在鏡片上面。是的&#xff0c;沒有猜錯&#xff0c;那是我們臉上油脂、汗液和各種不明物質的混合體。特別是在夏天的時候天氣太炎熱會經常出汗&#xff0c;眼鏡上會沾染…

2021職稱繼續教育--加快構建完整內需體系,形成國內國際雙循環相互促進新格局

單選題&#xff08;共7題&#xff0c;每題5分&#xff09; 1、根據本講&#xff0c;突破和推進“一帶一路”戰略&#xff0c;要滿足以企業為主體、以&#xff08;&#xff09;為導向的基本要求。 D、市場 2、根據本講&#xff0c;讓農村消費市場持續擴張的前提&#xff08;&am…

shell將文件分割成小塊文件

背景&#xff1a;某軟件最多支持1G的文件傳輸&#xff0c;需要對大文件進行切割。 方案1&#xff1a; 可以使用split命令將文件均分成10分片。以下是具體的命令示例&#xff1a; split -b $(($(du -b < 文件名) / 10)) 文件名 分片前綴 這里文件名是你想要分割的文件的名…

網絡架構三層到大二層的對比和選擇

在企業的網絡結構選擇中&#xff0c;有二層網絡和三層網絡結構兩種選擇。三層是按照邏輯拓撲結構進行的分類&#xff0c;匯聚層和接入層&#xff0c;流量縱向經過接入層、匯聚層網絡&#xff0c;收斂至骨干核心層。二層網絡結構沒有匯聚層。大二層網絡架構通常使用VLAN&#xf…

上海冠珠旗艦總店盛裝開業暨冠珠瓷磚中國美學設計巡回圓滿舉辦

上海&#xff0c;這座融合了東西方文化的國際化大都市&#xff0c;不僅是中國的時尚中心&#xff0c;也是全球潮流的匯聚地。在這里&#xff0c;古典與現代交織&#xff0c;傳統與前衛并存&#xff0c;為傳統色彩與現代設計的融合提供了得天獨厚的條件。 5月25日&#xff0c;上…

JWT-登錄后下發令牌

后端 寫一個jwt工具類&#xff0c;處理令牌的生成和校驗&#xff0c;如&#xff1a; 響應數據樣例&#xff1a; 前端要做的&#xff1a;

ts 中的 type 和 interface 有什么區別?

一、用法舉例 interface Person {name: stringage: number }const person: Person {name: Kite,age: 24 }type Person {name: stringage: number }const person: Person {name: Kite,age: 24 }二、翻閱 ts 的官方文檔&#xff1a; 1、interface 接口 TypeScript的核心原則…

Weblogic SSRF漏洞 [CVE-2014-4210]

漏洞復現環境搭建請參考 http://t.csdnimg.cn/svKal docker未能成功啟動redis請參考 http://t.csdnimg.cn/5osP3 漏洞原理 Weblogic的uddi組件提供了從其他服務器應用獲取數據的功能并且沒有對目標地址做過濾和限制&#xff0c;造成了SSRF漏洞&#xff0c;利用該漏洞可以向內…

【AJAX前端框架】Asynchronous Javascript And Xml

1 傳統請求及缺點 傳統的請求都有哪些&#xff1f; 直接在瀏覽器地址欄上輸入URL。點擊超鏈接提交form表單使用JS代碼發送請求 window.open(url)document.location.href urlwindow.location.href url… 傳統請求存在的問題 頁面全部刷新導致了用戶的體驗較差。傳統的請求導…

安泰電子:高壓功率放大器應用場合介紹

高壓功率放大器是一種電子設備&#xff0c;用于將低電壓信號放大到較高電壓水平&#xff0c;以滿足各種應用需求。它在多個領域中具有廣泛的應用&#xff0c;包括科學研究、工業生產、通信技術以及醫療設備。下面安泰電子將介紹高壓功率放大器的應用場合。 科學研究 高壓功率放…

【最優化方法】實驗一 熟悉MATLAB基本功能

實驗一  熟悉MATLAB基本功能 實驗的目的和要求&#xff1a;在本次實驗中&#xff0c;通過親臨使用MATLAB&#xff0c;對該軟件做一全面了解并掌握重點內容。 實驗內容&#xff1a; &#xff11;、全面了解MATLAB系統 &#xff12;、實驗常用工具的具體操作和功能 學習建…

在Open AI的Assistant API中,Thread代表什么?

在OpenAI的Assistant API中&#xff0c;Thread通常代表一系列相關的對話&#xff0c;保持對話的上下文和連貫性。這對于創建連續對話非常重要&#xff0c;因為它允許模型記住先前的交互&#xff0c;并在隨后的響應中參考這些信息。 具體作用 保持上下文&#xff1a;Thread可以…