*單個Map創建
Map<String, String> stringStringMap = Collections.singletonMap("reason", "同意");
- 使用匿名類初始化Map
List<Map<String,Object>> mapList=new ArrayList<>();mapList.add(new HashMap<String, Object>() {{put("min", 100);put("max", 200);}});mapList.add(new HashMap<String, Object>() {{put("min", 400);put("max", 800);}});mapList.add(new HashMap<String, Object>() {{put("min", 1000);put("max", 6000);}});
- hutool包工具
HashMap<String, String> of = MapUtil.of("1", "2");HashMap<String, String> of1 = (HashMap<String, String>) MapUtil.of(new Pair[]{Pair.of("11", "2"), Pair.of("1", "2")});Map<String, String> build = MapUtil.builder(new HashMap<String, String>()).put("key1", "value1").put("key3", "value3").put("key2", "value2").build();Map<Object, Object> colorMap = MapUtil.of(new String[][] {{"RED", "#FF0000"},{"GREEN", "#00FF00"},{"BLUE", "#0000FF"}
});
- Guava(要提前引入Guava依賴)
<dependency><groupId>com.google.guava</groupId><artifactId>guava</artifactId><version>28.1-jre</version></dependency>Map<String, String> map3 = ImmutableMap.of("張三", "34", "李四", "24");// 或者Map<String, String> map4 = ImmutableMap.<String, String>builder().put("張三", "34").put("李四", "24").build();*Java 9 及以上版本
// 使用Map.of()創建一個不可變的MapMap<String, String> map = Map.of("A", "k", "B", "v");
- Map.ofEntries() 方法（適用于 Java 9 及以上版本）
// 使用Map.ofEntries()創建一個不可變的MapMap<String, String> map = Map.ofEntries(Entry.of("A", "B"));
)
