求出數組中元素的總和

This program will help to find out the sum of elements in an array which is divisible by a number K. It uses the basic concept of modulo '%' or the remainder of a number.

該程序將幫助找出數組中被數字K整除的元素之和 。 它使用“％”模或數字余數的基本概念。

Program:

程序：

#include<iostream>
using namespace std;
int main(){
int n, ele;
cout<<"Enter the size of the array.\n";
cin>>n;
int A[n];
cout<<"Enter elements in the array\n";
for(int i =0;i<n;i++){
cin>>A[i];
}
cout<<"Enter the element to be divisible by.\n";
cin>>ele;
int sum = 0;
for(int i =0;i<n;i++){
if(A[i]%ele==0){
sum += A[i];
}
}
cout<<"The sum is "<<sum<<endl;
return 0;    
}

Output

輸出量

Enter the size of the array.
6
Enter elements in the array
2 3 4 5 6 7
Enter the element to be divisible by.
3
The sum is 9

翻譯自: https://www.includehelp.com/cpp-programs/sum-of-all-the-elements-in-an-array-divisible-by-a-given-number-k.aspx

求出數組中元素的總和