位運算使奇數+1 偶數-1

Problem: Take input from the user (N) and print all EVEN and ODD numbers between 1 to N.

問題：從用戶那里輸入(N)，并打印1至N之間的所有偶數和奇數編號。

Solution:

解：

• Input an integer number (N).

  輸入一個整數( N )。

• Run two separate loops from 1 to N.

  從1到N運行兩個單獨的循環。

• In the first loop, check the condition to check EVEN numbers and print them.

  在第一個循環中，檢查條件以檢查偶數并打印它們。

• In the second loop, check the condition to check ODD numbers and print them.

  在第二個循環中，檢查條件以檢查奇數編號并打印它們。

• To check EVEN/ODD number – find the remainder dividing by 2, if it is 0 then the number will be an EVEN number, else the number will be an ODD number.

  要檢查EVEN / ODD號碼-找到除以2的余數，如果為0，則該號碼將為EVEN號碼，否則該號碼將為ODD號碼。

C++ program:

C ++程序：

// C++ program to print all
// Even and Odd numbers from 1 to N
#include <iostream>
using namespace std;
// function : evenNumbers
// description: to print EVEN numbers only.
void evenNumbers(int n)
{
int i;
for (i = 1; i <= n; i++) {
//condition to check EVEN numbers
if (i % 2 == 0)
cout << i << " ";
}
cout << "\n";
}
// function : oddNumbers
// description: to print ODD numbers only.
void oddNumbers(int n)
{
int i;
for (i = 1; i <= n; i++) {
//condition to check ODD numbers
if (i % 2 != 0)
cout << i << " ";
}
cout << "\n";
}
// main code
int main()
{
int N;
// input the value of N
cout << "Enter the value of N (limit): ";
cin >> N;
cout << "EVEN numbers are...\n";
evenNumbers(N);
cout << "ODD numbers are...\n";
oddNumbers(N);
return 0;
}

Output

輸出量

RUN 1:
Enter the value of N (limit): 11
EVEN numbers are...
2 4 6 8 10
ODD numbers are...
1 3 5 7 9 11
RUN 2:
Enter the value of N (limit): 50
EVEN numbers are...
2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48 50
ODD numbers are...
1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49

翻譯自: https://www.includehelp.com/cpp-programs/print-all-even-and-odd-numbers-from-1-to-n.aspx

位運算使奇數+1 偶數-1