一串字符串轉換為ascii

Given an ASCII string (char[]) and we have to convert it into BYTE array (BYTE[]) in C.

給定一個ASCII字符串(char [])，我們必須將其轉換為C語言中的BYTE數組(BYTE [])。

Logic:

邏輯：

To convert an ASCII string to BYTE array, follow below-mentioned steps:

要將ASCII字符串轉換為BYTE數組，請執行以下步驟：

• Extract characters from the input string and get the character's value in integer/number format using %d format specifier, %d gives integer (number) i.e. BYTE value of any character.

  從輸入字符串中提取字符，并使用％d格式說明符以整數/數字格式獲取字符的值， ％d給出整數(數字)，即任何字符的BYTE值。

• Add these bytes (number) which is an integer value of an ASCII character to the output array.

  將這些字節(數字)(它是ASCII字符的整數值)添加到輸出數組中。

• After each iteration increase the input string's loop counter (loop) by 1 and output array's loop counter (i) by 1.

  每次迭代后，將輸入字符串的循環計數器( loop )增大1，將輸出數組的循環計數器( i )增大1。

Example:

例：

    Input: "Hello world!"
Output:
72
101
108
108
111
32 
119
111
114
108
100
33

C程序將ASCII char []轉換為BYTE數組 (C program to convert ASCII char[] to BYTE array)

In this example, ascii_str is an input string that contains "Hello world!", we are converting it to a BYTE array. Here, we created a function void string2ByteArray(char* input, BYTE* output), to convert ASCII string to BYTE array, the final output (array of integers) is storing in arr variable, which is passed as a reference in the function.

在此示例中， ascii_str是包含“ Hello world！”的輸入字符串。 ，我們正在將其轉換為BYTE數組。 在這里，我們創建了一個函數void string2ByteArray(char * input，BYTE * output) ， 將ASCII字符串轉換為BYTE array ，最終輸出(整數數組)存儲在arr變量中，該變量作為函數中的引用傳遞。

Note: Here, we created a typedef BYTE for unsigned char data type and as we know an unsigned char can store value from 0 to 255.

注意：在這里，我們為無符號字符數據類型創建了一個typedef BYTE ，眾所周知， 無符號字符可以存儲0到255之間的值。

Read more: typedef in C, unsigned char in C

： C語言中的typedef，C語言中的unsigned char

#include <stdio.h>
#include <string.h>
typedef unsigned char BYTE;
//function to convert string to byte array
void string2ByteArray(char* input, BYTE* output)
{
int loop;
int i;
loop = 0;
i = 0;
while(input[loop] != '\0')
{
output[i++] = input[loop++];
}
}
int main(){
char ascii_str[] = "Hello world!";
int len = strlen(ascii_str);
BYTE arr[len];
int i;
//converting string to BYTE[]
string2ByteArray(ascii_str, arr);
//printing
printf("ascii_str: %s\n", ascii_str);
printf("byte array is...\n");
for(i=0; i<len; i++)
{
printf("%c - %d\n", ascii_str[i], arr[i]);
}
printf("\n");
return 0;
}

Output

輸出量

ascii_str: Hello world!
byte array is...
H - 72
e - 101
l - 108
l - 108
o - 111
- 32 
w - 119
o - 111
r - 114
l - 108
d - 100
! - 33

Read more...

...

• Octal literals in C language

  C語言的八進制文字

• Working with octal numbers in C language

  使用C語言處理八進制數

• Working with hexadecimal numbers in C language

  使用C語言處理十六進制數

翻譯自: https://www.includehelp.com/c/convert-ascii-string-to-byte-array-in-c.aspx

一串字符串轉換為ascii