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#include

int main()

{

int i,j,k,t,m,a,b,c=0;

int x,y,z,n;

printf ("請按下面格式輸年-月-日\n");

printf("請輸入現在年月日：\n");

scanf ("%d-%d-%d",&i,&j,&k);

printf("請輸入出生年月日:\n");

scanf("%d-%d-%d",&x,&y,&z);

n=i-x+1;

printf("你的年齡是:%d\n",n);

switch(j)

{

case 1:m=k;break;

case 2:m=31+k;break;

case 3:m=59+k;break;

case 4:m=90+k;break;

case 5:m=120+k;break;

case 6:m=151+k;break;

case 7:m=181+k;break;

case 8:m=212+k;break;

case 9:m=243+k;break;

case 10:m=273+k;break;

case 11:m=304+k;break;

case 12:m=334+k;break;

}

switch(y)

{

case 1:a=z;break;

case 2:a=31+z;break;

case 3:a=59+z;break;

case 4:a=90+z;break;

case 5:a=120+z;break;

case 6:a=151+z;break;

case 7:a=181+z;break;

case 8:a=212+z;break;

case 9:a=243+z;break;

case 10:a=273+z;break;

case 11:a=304+z;break;

case 12:a=334+z;break;

}

for(b=x;b<=i;b++)

{

if (b%400==0)//(b%4==0&&b%100!=0)

c=c+1;

if(y<2)

c=c-1;

if(j<2)

c=c+1;

}

t=(i-x)*365+m-a+c;printf("出生到現在的天數：%d",t); return 0;

}