1028. List Sorting (25)

題目鏈接：http://www.patest.cn/contests/pat-a-practise/1028

題目：

1028. List Sorting (25)

時間限制

200 ms

內存限制

65536 kB

代碼長度限制

16000 B

判題程序

Standard

作者

CHEN, Yue

Excel can sort records according to any column. Now you are supposed to imitate this function.

Input

Each input file contains one test case. For each case, the first line contains two integers N (<=100000) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1

3 1
000007 James 85
000010 Amy 90
000001 Zoe 60

Sample Output 1

000001 Zoe 60
000007 James 85
000010 Amy 90

Sample Input 2

4 2
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 98

Sample Output 2

000010 Amy 90
000002 James 98
000007 James 85
000001 Zoe 60

Sample Input 3

4 3
000007 James 85
000010 Amy 90
000001 Zoe 60
000002 James 90

Sample Output 3

000001 Zoe 60
000007 James 85
000002 James 90
000010 Amy 90

分析：

接收數字來確定排序的方案，寫好結構體和排序就OK，難度不大

AC代碼：

#include<stdio.h>
#include<vector>
#include<string.h>
#include<algorithm>
using namespace std;
struct Student{char ID[7];char name[9];int grade;
};
bool cmp1(Student A, Student B){//依照學號排序return strcmp(A.ID, B.ID) < 0;
}
bool cmp2(Student A, Student  B){//依照名字排序。再依照學號排序if (strcmp(A.name, B.name) != 0)return strcmp(A.name, B.name) < 0;else return strcmp(A.ID, B.ID) < 0;
}
bool cmp3(Student A, Student B){//依照分數排序，再依照學號排序if (A.grade != B.grade)return A.grade < B.grade;else return strcmp(A.ID, B.ID) < 0;
}
vector<Student>V;
int main(void){//freopen("F://Temp/input.txt", "r", stdin);int n, k;while (scanf("%d", &n) != EOF){scanf("%d", &k);for (int i = 0; i < n; i++){Student tmp;scanf("%s%s%d", tmp.ID, tmp.name, &tmp.grade);V.push_back(tmp);}if (k == 1)sort(V.begin(), V.end(), cmp1);if (k == 2)sort(V.begin(), V.end(), cmp2);if (k == 3)sort(V.begin(), V.end(), cmp3);for (int i = 0; i < n; i++){printf("%s %s %d\n", V[i].ID, V[i].name, V[i].grade);}}return 0;
}

截圖：

——Apie陳小旭