1031 查驗身份證

題目鏈接：https://pintia.cn/problem-sets/994805260223102976/problems/994805290334011392

題解：

 1 #include <iostream>
 2 #include<cstdio>
 3 #include<string>
 4 using namespace std;
 5 
 6 int main() {
 7     int weigth[] = { 7,9,10,5,8,4,2,1,6,3,7,9,10,5,8,4,2 };
 8     int n, count = 0;
 9     cin >> n;
10     getchar();
11     string *str = new string[n];
12     for (int i = 0; i < n; i++)
13         getline(cin, str[i]);
14     for (int i = 0; i < n; i++) {
15         int Sum_weigth = 0;
16         char M;
17         for (int j = 0; j < 17; j++)
18             Sum_weigth = Sum_weigth + (str[i][j] - 48)*weigth[j];
19         int Z = Sum_weigth % 11;
20         switch (Z) {
21         case 0:
22             M = '1'; break;
23         case 1:
24             M = '0'; break;
25         case 2:
26             M = 'X'; break;
27         case 3:
28             M = '9'; break;
29         case 4:
30             M = '8'; break;
31         case 5:
32             M = '7'; break;
33         case 6:
34             M = '6'; break;
35         case 7:
36             M = '5'; break;
37         case 8:
38             M = '4'; break;
39         case 9:
40             M = '3'; break;
41         default:
42             M = '2'; break;
43         }
44         if (str[i][17] != M) cout << str[i] << endl;
45         else count++;
46     }
47     if (count == n) cout << "All passed";
48     return 0;
49 }

轉載于:https://www.cnblogs.com/Gzu_zb/p/9544721.html

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