需求：：前端根據后端的返回數據：畫統計圖；

1.動態獲取地域數據以及數據中的平均值，按照平均值降序排序；
說明：
X軸是動態的，有對應區域數據則展示；
X軸 區域數據降序排序；

代碼：

	@Overridepublic List<Map<String,Object>> getTimeData(HttpServletRequest request, Map<String, Object> paramMap) {List<Map<String,Object>> list = getCountData(request,paramMap);list = list.stream().filter(e -> (e.get("status").equals("關閉"))).collect(Collectors.toList());List<Map<String,Object>> resultList = new ArrayList<>();String[] reginArr = {"安徽","安順","北京","北美","長春","長沙","成都","承德","大連","武漢"};int[] count = new int[reginArr.length];double[] processTimeCount = new double[reginArr.length];double[] processTimeAvg = new double[reginArr.length];for (int i = 0; i < list.size(); i++) {String processTime = String.valueOf(list.get(i).get("processTime"));String region = String.valueOf(list.get(i).get("region")).trim();if(!processTime.contains(".")){list.get(i).put("processTime","0.0");}String processTime2 = String.valueOf(list.get(i).get("processTime"));for (int j = 0; j < reginArr.length; j++) {if(region.equals(reginArr[j].trim())){count[j] = count[j] + 1;  // 統計次數processTimeCount[j] = processTimeCount[j] + Double.parseDouble(processTime2);  // 統計合并值}}}// 計算平均值for (int i = 0; i < processTimeCount.length; i++) {processTimeAvg[i] =  processTimeCount[i]/count[i];// double類型的數據當分母的數值趨近0的時候，返回來的數值就是一個NAN:if(Double.isNaN(processTimeAvg[i])){processTimeAvg[i] = 0.0;}}// 將數據封裝集合for (int i = 0; i < reginArr.length; i++) {Map<String,Object> mapResult = new HashMap<>();String avg = String.valueOf(processTimeAvg[i]);mapResult.put("title",reginArr[i]);mapResult.put("value",avg.substring(0,avg.indexOf(".") +2));resultList.add(mapResult);}// 數據過濾List<Map<String,Object>> finalList = new ArrayList<>();// 過濾不需要的數據；for (int i = 0; i < resultList.size(); i++) {String value = String.valueOf(resultList.get(i).get("value"));if(!value.equals("0.0")){finalList.add(resultList.get(i));}}// 排序后最終輸出集合：List<Map<String,Object>> finalList2= new ArrayList<>();Double[] valueSort = new Double[finalList.size()];String[] titleSort = new String[finalList.size()];// 用數組存儲需要排序的元素；for (int i = 0; i < finalList.size(); i++) {valueSort[i] = Double.parseDouble(String.valueOf(finalList.get(i).get("value")));titleSort[i] = String.valueOf(finalList.get(i).get("title"));}// 多個數組排序；BubblSortUtils.bubbleSortDescMultipleDouble(valueSort,titleSort);// 根據排序結果封裝List；for (int i = 0; i < valueSort.length; i++) {String ch = String.valueOf(titleSort[i]);for (int j = 0; j < finalList.size(); j++) {String value = String.valueOf(finalList.get(j).get("title"));if(ch.equals(value)){finalList2.add(finalList.get(j));}}}// 添加排序字段：sortValuefor (int i = 0; i < finalList2.size(); i++) {finalList2.get(i).put("sortValue",i+1);}return finalList2;}

Postman接口測試：

總結： 代碼中有一個地域的數組：reginArr ，如果地域字典新增，還需維護這個字典，所以還是不夠靈活；參考【Java 動態數據統計圖】動態數據統計思路Demo（動態，排序）三（115）和【Java代碼優化】for循環，多if條件分支代碼優化一（110）中的優化方案二；有更靈活計算邏輯；