這是我自己的一個作業，用的是很基礎的代碼。
有錯誤的地方歡迎批評和指正！
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這里最容易出錯的地方在讀取數據后向數據庫表中插入數據是的數據格式！
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文件上傳的頁面
uploading.php
<html>
<body align = "center">
<form action = "DBConnect.php" method = "post" enctype = "multipart/form-data">
Upload a text file <input name = "myfile" type = "file" /></br></br>
<input type = "submit" value = "Upload this file"/></br></br>
</form>
<a href = "">Click here to find the format of text</a>
</body>
</html>
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接收（對數據的讀取）與對數據庫的操作界面
DBConnect.php
<?php
$content = $_FILES['myfile']; // 對文件格式的讀取，$_FILES方法
//print_r($content);
$string = file($content['name']);
//print_r($string);
//echo $string[0];
//exit(0);
$link = mysqli_connect("localhost","root","1234");
//create database sampleDB
mysqli_query($link,"create database $string[0]");
//create table mytbl
mysqli_query($link,"use $string[0]");
$tblQuery = "create table $string[1](";
$tblString="";
for($i=3;$i<count($string);$i++){
if(trim($string[$i]) == "row"){ // trim means remove space
break;
}else{
$col = explode(",",$string[$i]);
$tblString.=$col[0]." ".$col[1].",";
}
}
$tblQuery1 = $tblQuery.substr($tblString,0,-1).");";
mysqli_query($link,$tblQuery1);
//insert data to mytbl
$data = "insert into $string[1] values";
$data1String = "";
for($i=10;$i<count($string);$i++){
$data1 = explode(",",$string[$i]);
$data1String.="(".$data1[0].","."'".$data1[1]."'".",".$data1[2].",".$data1[3].","."'".$data1[4]."'".","."'".$data1[5]."'"." "."),";
}
// echo $data1String;
$tbldata = $data.substr($data1String,0,-1).";";
//echo $tbldata;
mysqli_query($link,$tbldata);
?>
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info.txt 【這是你自己要讀取的文件，里面的內容根據自己需求寫】
sampleDB
mytbl
columns
sno,int
sname,varchar(15)
age,int
gender,boolean
address,text
cellphone,varchar(11)
row
1,john,12,0,california,1212111
2,alice,15,1,new york,1241512
3,cindy,13,1,LA,1251455
4,joshua,14,0,philadelphia,2154412
