terminate called after throwing an instance of 'std::out_of_range' what(): basic_string::substr

運行時報錯：

terminate called after throwing an instance of 'std::out_of_range'
what(): ?basic_string::substr：__pos

Aborted (core dumped)

內存讀取越界。

解釋1：for example:
const std::string sTest( "test" );
sTest.substr( 0, 10 );
will raise the same exception, since you ask 10 characters, but only 5 ( sTest.length()) ) are available.

調試過，正常運行，無報錯。

解釋2：

Chances are you did something like:

std::string s("foo");

s.substr(5,1); //the length of the string is 3, 5 is out of bounds

調試過，確實會報錯，out_of_range

?

解決方案：查找substr方法前后代碼，排除可能的越界條件。