你可以使用正則表達式

(?:\\.|[^;\\]++)*

匹配未轉義分號之間的所有文本：

List matchList = new ArrayList();

try {

Pattern regex = Pattern.compile("(?:\\\\.|[^;\\\\]++)*");

Matcher regexMatcher = regex.matcher(subjectString);

while (regexMatcher.find()) {

matchList.add(regexMatcher.group());

}

說明：

(?: # Match either...

\\. # any escaped character

| # or...

[^;\\]++ # any character(s) except semicolon or backslash; possessive match

)* # Repeat any number of times.

由于嵌套量詞,占有性匹配()對于避免災難性回溯非常重要.