我通常使用標準庫中的ElementTree模塊解析XML。

它沒有給你一個字典，你得到了一個更有用的DOM結構，它允許你為孩子們遍歷每個元素。from xml.etree import ElementTree as ET

xml = ET.parse("

root_element = xml.getroot()

for child in root_element:

...

如果需要將其解析為字典，而不是從DOM樹中獲取所需的信息，則從根節點構建字典的遞歸函數如下：def xml_dict(node, path="", dic =None):

if dic == None:

dic = {}

name_prefix = path + ("." if path else "") + node.tag

numbers = set()

for similar_name in dic.keys():

if similar_name.startswith(name_prefix):

numbers.add(int (similar_name[len(name_prefix):].split(".")[0] ) )

if not numbers:

numbers.add(0)

index = max(numbers) + 1

name = name_prefix + str(index)

dic[name] = node.text + "<...>".join(childnode.tail

if childnode.tail is not None else

"" for childnode in node)

for childnode in node:

xml_dict(childnode, name, dic)

return dic

對于上面列出的XML，將生成此字典：{'A1': '\n \n <...>\n',

'A1.B1': '\n \n <...>\n ',

'A1.B1.C1': '"blah"',

'A1.B1.C2': '"blah"',

'A1.B2': '\n \n <...>\n ',

'A1.B2.C1': '"blah"',

'A1.B2.C2': '"blah"'}

(我發現DOM表單更有用)