一、Java 調用Python 提供的API接口，有多種方法，本文通過Python 提供的Rest API進行調用

二、在Python中創建一個REST API，你可以使用許多框架，其中兩個最流行的框架是Flask和Django REST framework。這兩個框架都提供了創建RESTful服務的強大功能

三、代碼

案例: 通過url帶參數傳遞

1、Python （Rest API）
這里需要提前安裝flask庫。

from flask import Flask, request, jsonifyapp = Flask(__name__)@app.route('/hello', methods=['GET'])
def process_data():param = request.args.get('param')result = "Hello "+param+"!"return jsonify({'result': result})if __name__ == '__main__':app.run(debug=True)

2、Java代碼

Java 是Maven項目，需要在pom.xml中導入okhttp包：

     <dependency><groupId>com.squareup.okhttp3</groupId><artifactId>okhttp</artifactId><version>4.9.1</version></dependency>

Java代碼如下：

import okhttp3.*;import java.io.IOException;public class JavaClient {public static final MediaType JSON = MediaType.parse("application/json; charset=utf-8");OkHttpClient client = new OkHttpClient();String get(String url) throws IOException {Request request = new Request.Builder().url(url).build();try (Response response = client.newCall(request).execute()) {return response.body().string();}}public static void main(String[] args) {JavaClient client = new JavaClient();String response = null;try {response = client.get("http://localhost:5000/hello?param=jieke");System.out.println(response);} catch (IOException e) {e.printStackTrace();}}
}