前言

個人小記

---

一、代碼

#include<stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#define MAX_NODE 10
#define MAX_LEN 100
#define key(n)(n)?(n->key):(-1)
typedef struct Node
{int key;struct Node* lchild,*rchild;
}Node;Node* init_node(int key)
{Node* node=(Node*)malloc(sizeof(Node));node->key=key;node->lchild=node->rchild=NULL;return node;
}Node* insert(Node* root,int key)
{if(root==NULL)return init_node(key);if(rand()%2)root->lchild=insert(root->lchild,key);else root->rchild=insert(root->rchild,key);return root;
}Node* getnewtree(Node* root,int n)
{for(int i=0;i<n;i++){root=insert(root,rand()%100);}return root;
}void clear(Node* root)
{if(root==NULL)return ;clear(root->lchild);clear(root->rchild);free(root);return ;
}char buff[MAX_LEN];
int len;
void __serial(Node* root)
{if(root==NULL)return ;len+=snprintf(buff+len,100,"%d",root->key);if(root->lchild==NULL&&root->rchild==NULL)return ;len+=snprintf(buff+len,100,"(");__serial(root->lchild);if(root->rchild){len+=snprintf(buff+len,100,",");__serial(root->rchild);}len+=snprintf(buff+len,100,")");return ;
}void serial(Node* root)
{memset(buff,0,sizeof(buff));len=0;__serial(root);return ;
}void output(Node* root)
{if(root==NULL)return ;printf("%d(%d,%d)\n",key(root),key(root->lchild),key(root->rchild));output(root->lchild);output(root->rchild);
}Node* diserial(char buff[],int n)
{Node* root=NULL;Node* p=NULL;int top=-1,state=0,fag=0;Node** stack=(Node**)malloc(sizeof(Node*)*MAX_NODE);for(int i=0;i<n;i++){switch(state){case 0:{if(buff[i]<='9'&&buff[i]>='0')state=1;if(buff[i]=='(')state=2;if(buff[i]==',')state=3;if(buff[i]==')')state=4;i--;}break;case 1:{int key=0;while(buff[i]<='9'&&buff[i]>='0'){key=key*10+(buff[i]-'0');i++;}p=init_node(key);if(fag==0&&top>=0)stack[top]->lchild=p;if(fag==1&&top>=0)stack[top]->rchild=p;i--;state=0;}break;case 2:{stack[++top]=p;fag=0;state=0;}break;case 3:{fag=1;state=0;}break;case 4:{root=stack[top--];state=0;}break;}}free(stack);
return root;
}int main()
{srand((unsigned)time(0));Node* root=NULL;root=getnewtree(root,MAX_NODE);serial(root);output(root);printf("廣義表為:\n");printf("%s\n",buff);Node* new_root=diserial(buff,len);printf("反序列化結果為:"\n);output(new_root);clear(root);clear(new_root);return 0;
}

二、結果

10(35,0)
35(41,2)
41(-1,25)
25(-1,-1)
2(-1,-1)
0(94,79)
94(65,-1)
65(-1,-1)
79(44,-1)
44(-1,-1)
廣義表為:
10(35(41(,25),2),0(94(65),79(44)))
反序列化結果為:
10(35,0)
35(41,2)
41(-1,25)
25(-1,-1)
2(-1,-1)
0(94,79)
94(65,-1)
65(-1,-1)
79(44,-1)
44(-1,-1)