math.pow int

數學類靜態int min(int i1，int i2) (Math Class static int min(int i1 , int i2) )

• This method is available in java.lang package.

  此方法在java.lang包中可用。

• This method is used to return the minimum one of both the given arguments or in other words this method returns the smallest value of the given two arguments.

  此方法用于返回給定兩個參數中的最小值。換句話說，此方法返回給定兩個參數中的最小值。

• This is a static method so this method is accessible with the class name too.

  這是一個靜態方法，因此也可以使用類名訪問此方法。

• The return type of this method is int, it returns the smallest element from the given two arguments.

  此方法的返回類型為int ，它從給定的兩個參數中返回最小的元素。

• This method accepts two arguments of integer (int) types.

  此方法接受兩個整數( int )類型的參數。

• This method does not throw any exception.

  此方法不會引發任何異常。

Syntax:

句法：

    public static int min(int i1, int i2){
}

Parameter(s): int i1, int i2 – two integer values, in which we have to find the smallest/minimum value.

參數： int i1，int i2 –兩個整數值，我們必須在其中找到最小/最小值。

Return value:

返回值：

The return type of this method is int, it returns the smallest/minimum value.

此方法的返回類型為int ，它返回最小/最小值。

Note:

注意：

• If we pass "NaN" (Not a Number), it returns the same value i.e. "NaN".

  如果我們傳遞“ NaN”(不是數字)，它將返回相同的值，即“ NaN”。

• If we pass zero (-0 or 0), it returns the 0.

  如果傳遞零(-0或0)，則返回0。

• If we pass the same values in both parameters, it returns the same value.

  如果我們在兩個參數中傳遞相同的值，則它將返回相同的值。

Java程序演示min(int i1，int i2)方法的示例 (Java program to demonstrate example of min(int i1,int i2) method)

// Java program to demonstrate the example of 
// min(int i1, int i2) method
public class MinDoubleTypeMethod  {
public static void main(String[] args) {
// declaring variables
int i1 = -0;
int i2 = 0;
int i3 = -2;
int i4 = 124;
// displaying the values
System.out.println("i1: " + i1);
System.out.println("i2: " + i2);
System.out.println("i3: " + i3);
System.out.println("i4: " + i4);
// Here , we will get (-2) because we are passing 
// parameter whose value is (-0,0)
System.out.println("Math. min(i1,i3): " + Math.min(i1, i3));
// Here , we will get (0) because we are passing 
// parameter whose value is (-0,0)
System.out.println("Math.min(i1,i2): " + Math.min(i1, i2));
// Here , we will get (0) and we are passing 
// parameter whose value is (0,124)
System.out.println("Math.min(i2,i4): " + Math.min(i2, i4));
}
}

Output

輸出量

E:\Programs>javac MinDoubleTypeMethod.java
E:\Programs>java MinDoubleTypeMethod
i1: 0
i2: 0
i3: -2
i4: 124
Math. min(i1,i3): -2
Math.min(i1,i2): 0
Math.min(i2,i4): 0

翻譯自: https://www.includehelp.com/java/math-class-static-int-min-int-i1-int-i2-with-example.aspx

math.pow int