c語言100位整數變量聲明

Here, we will learn how we can declare an integer variable dynamically and how to print address of declared memory block?

在這里，我們將學習如何動態聲明整數變量，以及如何打印聲明的內存塊的地址？

In C++ programming, we can declare memory at run time for any type variable like char, int, float, integer array etc. To declare memory at run time (dynamically), we use new operator. I would recommend reading about new operator first.

在C ++編程中，我們可以在運行時為char，int，float，integer array等任何類型的變量聲明內存。要在運行時(動態)聲明內存，請使用new運算符。 我建議先閱讀有關新運算符的信息 。

Consider the following program:

考慮以下程序：

#include <iostream>
using namespace std;
int main()
{
//integer pointer declartion
//It will contain the address of dynamically created 
//memory blocks for an integer variable 
int *ptr;
//new will create memory blocks at run time 
//for an integer variable
ptr=new int;
cout<<"Address of ptr: "<<(&ptr)<<endl;
cout<<"Address that ptr contains: "<<ptr<<endl;
//again assigning it run time
ptr=new int;
cout<<"Address of ptr: "<<(&ptr)<<endl;
cout<<"Address that ptr contains: "<<ptr<<endl;
//deallocating...
delete (ptr);
return 0;	
}

輸出量 (Output)

    Address of ptr: 0x7ffebe87bb98Address that ptr contains: 0x2b31e4097c20Address of ptr: 0x7ffebe87bb98Address that ptr contains: 0x2b31e4098c50

Here we are declaring an integer pointer ptr and printing the address of ptr by using &ptr along with stored dynamically allocated memory block.

在這里，我們聲明的整數指針PTR以及通過使用＆PTR與存儲動態分配的存儲塊沿著打印PTR的地址。

After that we are declaring memory for integer again and printing the same.

之后，我們再次聲明整數的內存并打印該整數。

From this example - we can understand memory blocks are allocating dynamically, each time different memory blocks are storing in the pointer ptr.

從這個例子中，我們可以理解每次將不同的存儲塊存儲在指針ptr中時，存儲塊都是動態分配的。

翻譯自: https://www.includehelp.com/code-snippets/cpp-declare-integer-variable-dynamically-print-the-memory-addresses.aspx

c語言100位整數變量聲明