博弈論 斯坦福game theory stanford week 3.2_


title: 博弈論 斯坦福game theory stanford week 3-1
tags: note
notebook: 6- 英文課程-15-game theory
---

博弈論 斯坦福game theory stanford week 3-1

習題

第 1 個問題

img_5d8fa8d4ec2efce7a8e96c6cf9172115.png

We say that a game is dominance solvable, if iterative deletion of strictly dominated strategies yields a unique outcome. True or false: The above game si dominance solvable. Hint: Consider both pure strategies and mixed strategies to do your domination.

a) True;

正確 
(a) is correct, the game is dominance solvable.For player 2, R is dominated by a mixed strategy between L and M (for example, play L with probability 1/2 and M with probability 1/2).
Once R is removed, for player 1 D is dominated by U.
Finally, once R and D are removed, M is dominated by L.
Since the process of iterative deletion of strictly dominated strategies yields the unique outcome (U,L), the game is dominance solvable.

b) False.

第 2 個問題

正確
1 / 1 分
2。第 2 個問題
In order to illustrate the problem that arises when iteratively eliminating weakly dominated strategies, consider the following game:

img_5d8fa8d4ec2efce7a8e96c6cf9172115.png

True or false: in the above game the order of elimination of weakly dominated strategies does not matter (that is, the final outcome is the same regardless of the order in which weakly dominated strategies are eliminated.).

[Hint: start the process of iterative elimination of weakly dominated strategies by eliminating different strategies at the beginning of the process.]

a) True;

b) False.

正確 
(b) is correct, in the previous game the order of elimination of weakly dominated strategies does matter.Consider the following attempts:
If we start by eliminating the weakly dominated strategy L:
For 2, L is weakly dominated by R.
Once L is removed, for 1 U is weakly dominated by D.
Once L and U are removed, M is strictly dominated by R.
The outcome of this process of elimination is (D,R).
If we start by eliminating the weakly dominated strategy M:
For 2, M is weakly dominated by R.
Once M is removed, for 1 D is weakly dominated by U.
Once M and D are removed, L is strictly dominated by R.
The outcome of this process of elimination is (U,R).
Then, the order of elimination of weakly dominated strategies does affect the outcome of the process.

第 3 個問題
正確
1 / 1 分

3。第 3 個問題

Consider the matching pennies game:

img_4e78d3e350ddef5e02491795ea90276d.png

Which is a maxmin strategy for player 1:

a) Play Left.

b) Play Right.

c) Play Left and Right with probability 1/2.

正確 
(c) is true.Recall from lecture: S1=argmaxs′1∈S1mins2∈S2u1(s′1,s2)
Given a strategy of 1: play Left with probability p and Right with 1?p (0≤p≤1):
If p>1/2, s2=Right leads 1 to earn (?2)p+2(1?p)<0;
If p<1/2, s2=Left leads 1 to earn 2p+(?2)(1?p)<0;
If p=1/2, then regardless of 2's strategy 1 earns 0.
Thus p=1/2 is the maxmin strategy.

d) It doesn't exist.

第 4 個問題

正確
1 / 1 分
4。第 4 個問題
Consider the matching pennies game:

img_00652fdc20dadfec04a87a5e8b53cdc6.png

Apply the Minimax theorem presented in lecture 3-4 to find the payoff that any player must receive in any Nash Equilibrium:

a) 2;

b) -2;

c) 1;

d) 0.

正確 
(d) is true.Since the previous game is a (finite) two-player, zero-sum game, by the theorem presented in the lecture we know that in any Nash equilibrium each player receives a payoff that is equal to both his maximin value and his minimax value.
From the previous question we know that each player's maximin strategy is to play Left and Right with probability 1/2, which gives an expected payoff (maximin value) of 0.

第 5 個問題

正確
1 / 1 分
5。第 5 個問題
img_e946047d6d0a6437faed171541e36809.png

Consider the following assignment device (for example a fair coin):

With probability 1/2 it tells players 1 and 2 to play B, and with probability 1/2 it tells them to play F.
Both players know that the device will follow this rule.
What is the expected payoff of each player when both players follow the recommendations made by the device? If one of players follows the recommendation, does the other player have an incentive to follow the recommendation as well?

a) Expected payoff =2; player has an incentive to follow the recommendation.

b) Expected payoff =1; player does not an incentive to follow the recommendation.

c) Expected payoff =1.5; player has an incentive to follow the recommendation.

正確 
(c) is true.If both players follow the recommendation of the device, they will play (B,B) with probability 1/2 and (F,F) with probability 1/2. Then, the expected payoff is 1/2?2+1/2?1=1.5.
It is easy to check that if one of the players is following the recommendation, then the other player has an incentive to do the same:
Suppose that player 1 follows the recommendation of the device.
When player 2 is told to play B, he/she knows that player 1 was also told to play B (and that is the strategy that he/she will play).
Player's 2 best response to player 1 playing B is to also play B.
The same holds when player 2 is told to play F. Therefore, player 2 will follow what the device tells him/her to do.

d) Expected payoff =1.5; player does not have an incentive to follow the recommendation.

本文來自互聯網用戶投稿,該文觀點僅代表作者本人,不代表本站立場。本站僅提供信息存儲空間服務,不擁有所有權,不承擔相關法律責任。
如若轉載,請注明出處:http://www.pswp.cn/news/539245.shtml
繁體地址,請注明出處:http://hk.pswp.cn/news/539245.shtml
英文地址,請注明出處:http://en.pswp.cn/news/539245.shtml

如若內容造成侵權/違法違規/事實不符,請聯系多彩編程網進行投訴反饋email:809451989@qq.com,一經查實,立即刪除!

相關文章

redis 值字符串前面部分亂碼_redis key亂碼

{"moduleinfo":{"card_count":[{"count_phone":1,"count":1}],"search_count":[{"count_phone":9,"count":9}]},"card":[{"des":"兼容Redis協議標準的、提供持久化的內存數據…

Hive的使用之腳本文件

好處 在實際開發中&#xff0c;遇到復雜的hivesql&#xff0c;在文件里先寫好再執行&#xff0c;比直接在控制臺寫更高效&#xff0c;糾錯&#xff0c;修改更方便&#xff0c;也易于后期維護。 [hadoophello110 ~]$ 模式 在hive沒有啟動的時候&#xff0c;非hive內&#xff0c…

nestjs swagger文檔調用需要鑒權的接口

目標 nestjs經常需要設置一些鑒權&#xff08;登錄后&#xff09;才能訪問的接口&#xff0c;但是生成的swagger文檔可以發起接口請求&#xff0c;文檔發起的請求默認是不攜帶登錄token的&#xff0c;所以需要移除swagger文檔發起請求的守衛攔截。 nestjs守衛攔截設置見另一篇…

ajax預加載html seo,前端性能優化 — JS預加載和懶加載

JS預加載需求&#xff1a;有時我們需要實現例如快速快速切換頁面、圖片之類的功能時&#xff0c;能盡快的加載出我們所需的圖片會極大提升用戶體驗&#xff0c;這時用預加載將圖片先緩存到瀏覽器&#xff0c;用戶使用需顯示圖片時無疑會順暢很多。核心&#xff1a;當一個圖片在…

面向對象、繼承、抽象方法重載知識點整理

面向過程、面向對象 面向過程&#xff1a;從開始到結束自己獨立完成 面向對象&#xff1a;將一個事物劃分為單體來各自實現區域性的功能&#xff0c;最后通過調用組合完成 類、對象 類&#xff1a;某一些具有共同特征的物體 對象&#xff1a;指某一種具體的物體&#xff0c;屬于…

python for循環n次_Python入門10 —— for循環

1.字符串依次取值 students [egon, lxx, alex] i 0 while i < 3: print(students[i]) i 1 2.針對循環取值操作&#xff0c;while循環并不擅長&#xff0c;于是python提供一個專門循環取值操作&#xff1a;for循環 students [egon, lxx, alex] for x in students: # 有幾…

hive與依賴環境的交互

與linux交互命令 格式 在linux的命令前加上!&#xff08;英文感嘆號&#xff09;&#xff0c;以;&#xff08;英文分號結尾&#xff09; 操作實例 !ls; !pwd; hive> !ls; app derby.log hadoop-2.7.2.tar.gz jdk-8u73-linux-x64.tar.gz metastore_db t.sql hive> !pw…

和平精英顯示服務器人數太多,和平精英到底有多差 導致玩家紛紛國際服

原標題&#xff1a;和平精英到底有多差 導致玩家紛紛國際服和平精英上線以來爭議不斷&#xff0c;百分之九十九是對和平精英的各種不滿&#xff0c;還有百分之一是喜歡和平精英&#xff0c;認為刺激戰場已經免費給我們玩&#xff0c;讓騰訊虧了很多錢&#xff0c;現在和平精英上…

python中的wx_配置 Python的wxWidgets可視開發環境 | 學步園

注&#xff1a;轉載請注明出處 一、下載 Python 2.5.1 這一步是必須做的&#xff0c;下載 Python 語言的 SDK 下載地址(直接復制到迅雷)&#xff1a;點擊下載 下載完成后安裝 Python 2.5.1&#xff0c;注意安裝路徑中不要有空格&#xff0c;不然會引起一些問題。 二、下載 wxPy…

的write方法有哪些參數_向子進程傳遞大量數據的方法

如何傳遞大型數據給子進程昨天的一篇文章中&#xff0c;我們說到如果想向一個子進程傳輸多于32767個字符的數據&#xff0c;我們需要尋找其他的方法(而不是命令行參數)來實現。我們能想到的第一個方法是&#xff1a;WM_COPYDATA。當子進程創建并進入消息循環后&#xff0c;我們…

厲害了!中關村軟件園人工智能軍團有料有看點

人工智能已成為當下全球科技界的新熱點&#xff0c;中外競相攀登這座劃時代的科技高峰。上月&#xff0c;國務院印發《新一代人工智能發展規劃》&#xff0c;明確將人工智能作為未來國家重要的發展戰略。《規劃》提出前瞻布局新一代人工智能重大科技項目&#xff0c;到2030年中…

Hive的使用之hwi

概述 hwi是hive開發的網頁形式查看數據。方便非專業人士使用。 安裝步驟 1、下載hive源碼包 地址&#xff1a;http://apache.fayea.com/hive/ apache-hive-2.1.0-src.tar.gz 2、打包war 解壓apache-hive-2.1.0-src.tar.gz源碼包&#xff0c;進入到 C:\Users\zengmg\Deskto…

c 服務器傳輸大文件,cend.me:不須經過服務器,直接點對點的文件傳輸免費服務...

要傳送文件給遠程的手機、平板、電腦等設備&#xff0c;通常的做法就是先將文件上傳到服務器存放&#xff0c;然后再從服務器下載&#xff0c;這樣的做法看似合理&#xff0c;但如果上傳的同時就由遠程的設備來接收&#xff0c;不要經過服務器&#xff0c;這樣就能更節省上、下…

win10系統遷移后系統重裝_win7/win10系統遷移到新SSD硬盤的方法

隨著固態硬盤的普及&#xff0c;越來越多的朋友把電腦的硬盤換成了固態&#xff0c;原來的機械硬盤當數據盤使用&#xff0c;關于在固態硬盤中安裝系統&#xff0c;那是簡單的&#xff0c;和機械硬盤一樣&#xff0c;當是對原來的系統比較重要&#xff0c;不能重裝的朋友來說&a…

hive參數配置使用

概述 set命令設置hive的參數。 ${} 可以獲取配置項的值&#xff0c;作為參數使用。 在啟動hive時可以傳入配置項啟動。 hive參數初始化配置set命令~/.hiverc hive參數介紹 輸入set&#xff0c;可以查看所有可設置項和現在設置項的值。 hive> set; 項太多了&#xff…

Thrift源碼學習二——Server層

Thrift 提供了如圖五種模式&#xff1a;TSimpleServer、TNonblockingServer、THsHaServer、TThreadPoolServer、TThreadSelectorServer ?? TSimpleServer、TThreadPoolServer 屬于阻塞模型 TNonblockingServer、THsHaServer、TThreadedSelectorServer 屬于非阻塞模型 TServer…

linux top 命令可視化_25個Linux性能監控工具

一段時間以來&#xff0c;我們在網上向讀者介紹了如何為Linux以及類Linux操作系統配置多種不同的性能監控工具。在這篇文章中我們將羅列一系列使用最頻繁的性能監控工具&#xff0c;并對介紹到的每一個工具提供了相應的簡介鏈接&#xff0c;大致將其劃分為兩類&#xff0c;基于…

base64是哪個jar包的_漲知識 | 用maven輕松管理jar包

前言相信只要做過 Java 開發的童鞋們&#xff0c;對 Ant 想必都不陌生&#xff0c;我們往往使用 Ant 來構建項目&#xff0c;尤其是涉及到特別繁雜的工作量&#xff0c;一個 build.xml 能夠完成編譯、測試、打包、部署等很多任務&#xff0c;這在很大的程度上解放了程序員們的雙…

Hive數據類型

概述 Hive的內置數據類型可以分為兩大類&#xff1a;(1)、基礎數據類型&#xff1b;(2)、復雜數據類型。 基礎數據類型 數據類型 所占字節 開始支持版本 TINYINT 1byte&#xff0c;-128 ~ 127 SMALLINT 2byte&#xff0c;-32,768 ~ 32,767 INT 4byte,-2,147,483,648 ~ 2,14…

JMS(Java消息服務)與消息隊列ActiveMQ基本使用(一)

最近的項目中用到了mq&#xff0c;之前自己一直在碼農一樣的照葫蘆畫瓢。最近幾天研究了下&#xff0c;把自己所有看下來的文檔和了解總結一下。 一. 認識JMS 1.概述 對于JMS,百度百科&#xff0c;是這樣介紹的&#xff1a;JMS即Java消息服務&#xff08;Java Message Service&…