代碼如下
用戶名:
密???碼:
$("#login_submit").bind("click",function(){
var type = "post";
var url = "index.php?m=admin&c=index&a=checkLogin";
var formArrays = $("#admin_form").serializeArray();
var requestData = {};
for(var i=0; i
//requestData[formArrays[i].name] = formArrays[i].value;
//console.log(typeof formArrays[i].name);
requestData[formArrays[i].name] = formArrays[i].value;
}
// 如果使用{ name: "John", time: "2pm" } 跳轉通過$_POST 獲取到的值沒有問題,但是如果是上面的requestData 則會返回當前頁面的html
//requestData = { login_name: "John", login_password: "2pm",m:"admin",c:"index",a:"checkLogin" };
console.log(typeof requestData);
var dataType = "json";
$.post(url,requestData,function(data){alert(data);});
});