Take input number from the user and print its reverse.
從用戶處獲取輸入號碼并打印其反面。
Example:
例：
Input:
12345
Output:
54321
Here, we are implementing program to reversing a given number using 2 different ways.
在這里，我們正在實施程序，以使用2種不同的方式來反轉給定的數字 。
1) Famous approach for reversing the number: Take input from the user and typecast into an integer, then iterate in the loop till num is not become zero, inside the loop:
1) 逆轉數字的著名方法 ：從用戶輸入并將其類型轉換為整數，然后在循環中循環直到num在循環內不為零：
Find out the remainder.
找出其余的。
Using this: rev_num = rev_num * 10 + remainder.
使用這個：rev_num = rev_num * 10 +余數。
Update that number by diving by 10.
通過跳水10來更新該數字。
After coming out of the loop printing the reverse number.
退出循環后，打印反向編號。
if __name__ == "__main__" :
# take string input from user
num = int(input('Enter a number: '))
rev_num = 0
# iterate the loop till num is not equal to zero
while(num) :
rem = num % 10
rev_num = rev_num* 10 + rem
num //= 10
print('Reverse number is: ', rev_num)
Output
輸出量
Enter a number: 12345
Reverse number is: 54321
2) Make a user-defined function for reversing the Number: Take input from the user and typecast into integer, thenreverseNum() function call.
2) 制作一個用于反轉Number的用戶定義函數 ：從用戶那里輸入輸入并將其類型轉換為整數，然后調用verseNum()函數。
Inside the function:
函數內部：
Iterate in the loop till num does not become zero:
在循環中迭代，直到num不為零：
Find out the remainder.
找出其余的。
Using this: rev_num = rev_num * 10 + remainder.
使用這個：rev_num = rev_num * 10 +余數。
Update that number by diving by 10.
通過跳水10來更新該數字。
After coming out of the loop returning the reverse number to the main.
退出循環后，將反向編號返回到主編號。
# define a function for finding
# reverse of the number
def reverseNum(num) :
rev_num = 0
# iterate the loop till num is not equal to zero
while(num) :
rem = num % 10
rev_num = rev_num* 10 + rem
num //= 10
return rev_num
# Main() method
if __name__ == "__main__" :
# take string input from user
num = int(input('Enter a number: '))
print('Reverse number is: ', reverseNum(num))
Output
輸出量
Enter a number: 12345
Reverse number is: 54321
翻譯自: https://www.includehelp.com/python/program-to-reverse-a-given-number-2-different-ways.aspx
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