publicvoiddoGet(HttpServletRequestrequest,HttpServletResponseresponse)throwsIOException,ServletException{//TODOAuto-generatedmethodstubXzdatasqlTool=newXzdata();//初始化并...

public void doGet(HttpServletRequest request,HttpServletResponse response) throws IOException,ServletException{

// TODO Auto-generated method stub

Xzdata sqlTool = new Xzdata(); // 初始化并且鏈接數據庫

System.out.println("連接數據庫成功!");

String sql = "select * from MyTable";

ResultSet rs = sqlTool.edb.getTableResult(sql);

ResultVO resVo = new ResultVO();

List listvo = new ArrayList();

try {//捕捉異常

while (rs.next()) {

resVo.setWages(rs.getString("DATAS"));

resVo.setYear(rs.getString("YEAR"));

resVo.setMonth(rs.getString("MONTH"));

resVo.setDay(rs.getString("DAY"));

listvo.add(resVo);

}

} catch (SQLException e) {

// TODO Auto-generated catch block

e.printStackTrace();

}

JSONArray jsonarr = JSONArray.fromObject(listvo); // java字符串轉為為json對象

PrintWriter out = response.getWriter();

out.write(jsonarr.toString());

out.close();

}

public void doPost(HttpServletRequest request,HttpServletResponse response) throws IOException,ServletException{

doGet(request,response);

}

把查出的數據賦值給resVo時，后取出的數據會覆蓋之前的resVo，這個可以理解，但是為什么已經放進listvo里的resVo也會被后取到的數據替換？如何解決？

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