fastjson 轉換成map
HashMap<String,String> map = JSON.parseObject(jsonStr,new TypeReference<HashMap<String,String>>() {});
?
fastjson 轉換成list
List<Person> list = new ArrayList<Person>(); ?
list = JSON.parseArray(jasonArray.toString, Person.class); ?
轉載于:https://www.cnblogs.com/zjm-1/p/9413908.html
